3(2Y^2/2)=5X-5

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Solution for 3(2Y^2/2)=5X-5 equation: 


x in (-oo:+oo)

3*((2*Y^2)/2) = 5*X-5 // - 5*X-5

3*((2*Y^2)/2)-(5*X)+5 = 0

3*((2*Y^2)/2)-5*X+5 = 0

3*Y^2-5*X+5 = 0

x należy do R

x in (-oo:+oo)

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